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Home » We reduce $ f(x) \equiv (x^2 + 1)^2025 + 1 \pmodd(x) $. - Portal da AcÃºstica

We reduce $ f(x) \equiv (x^2 + 1)^2025 + 1 \pmodd(x) $. - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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10^2 = 58 + 2ab \implies 100 = 58 + 2ab \implies 2ab = 42 \implies ab...
Sustituimos en la identidad:
a^3 + b^3 = (10)(58 - 21) = 10 \times 37 = 370
Por lo tanto, el valor de $a^3 + b^3$ es $\boxed{370}$.
Pregunta: Si $x + y = 5$ y $xy = 6$, encuentra el valor de $x^2 + y^2$...
Usamos la identidad:
x^2 + y^2 = (x + y)^2 - 2xy
Sustituyendo los valores dados:
x^2 + y^2 = 5^2 - 2 \times 6 = 25 - 12 = 13
Por lo tanto, el valor de $x^2 + y^2$ es $\boxed{13}$.

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