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Home » Thus, the vector is $\boxed\beginpmatrix 2 \\ 13 \\ 8 \endpmatrix$. - Portal da AcÃºstica

Thus, the vector is $\boxed\beginpmatrix 2 \\ 13 \\ 8 \endpmatrix$. - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Simplify: \( 50 = 5 \times \text{Height} \).

📌 Divide by 5: \(\text{Height} = 10 \).

📌 Therefore, the height of the triangle is 10 units.

📌 Solve for \( x \) in the equation \( 4x^2 - 12x + 9 = 0 \).

📌 This is a quadratic equation, which can be factored as:

📌 Recognize it as a perfect square: \( (2x - 3)^2 = 0 \).

📌 Solve for \( x \): \( 2x - 3 = 0 \).

📌 Add 3: \( 2x = 3 \).

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\[ k = 2h - 4 \]
Substitute \( k = 2h - 4 \) into the first equation:
\[ 5h + 3(2h - 4) = 15 \]
Simplify and solve for \( h \):
\[ 5h + 6h - 12 = 15 \]
\[ 11h - 12 = 15 \]
Add 12 to both sides:
\[ 11h = 27 \]
Divide by 11:
\[ h = \frac{27}{11} \]

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