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Home » Thus, the required matrix is \(oxedeginpmatrix 0 & -2 \ 2 & 0 \endpmatrix\). - Portal da AcÃºstica

Thus, the required matrix is \(oxedeginpmatrix 0 & -2 \ 2 & 0 \endpmatrix\). - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Now, compute the length:

📌 l = 2 \times \frac{14}{3} + 3 = \frac{28}{3} + \frac{9}{3} = \frac{37}{3} \approx 12.33 \text{ meters}

📌 Thus, the dimensions are width \(\frac{14}{3}\) m and length \(\frac{37}{3}\) m.

📌 Final dimensions: width \(\boxed{\dfrac{14}{3}}\) m, length \(\boxed{\dfrac{37}{3}}\) m.

📌 A philosopher of science studying the nature of scientific knowledge considers a logical sequence of hypotheses: Suppose a researcher forms hypotheses such that each new hypothesis is supported by two independent pieces of evidence, each of which increases the credibility of the hypothesis by 25%. If the initial credibility is 40%, what is the credibility after adding 4 such independent pieces of evidence?

📌 Let the initial credibility be \(C_0 = 40\% = 0.4\).

📌 Each piece of independent evidence increases credibility by 25% of the **current** credibility. This is multiplicative: each new evidence multiplies credibility by \(1.25\).

📌 After 4 independent pieces, the credibility is:

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