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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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\(x^4\): 1 = 1 â
\(x^3\): \(a - 1 = 3 \Rightarrow a = 4\)
\(x^2\): \(b - a + 1 = -2\), \(b - 4 + 1 = -2 \Rightarrow b = 1\)
\(x\): \(2a - b = 1 \Rightarrow 8 - 1 = 7
e 1\) â
Mistake â try correct expansion:
Now add \(Ax + B\) (since divisor is quadratic, remainder is linear: \...
x^4 + (a - 1)x^3 + (b - a + 1)x^2 + (a - b + A)x + (b + B)
Match:
\(x^2\): \(b - a + 1 = -2 \Rightarrow b - 4 + 1 = -2 \Rightarrow b = 1...

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