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Home » The component of \(\mathbfv\) perpendicular to \(\mathbfc\) is given by: - Portal da AcÃºstica

The component of \(\mathbfv\) perpendicular to \(\mathbfc\) is given by: - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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To find \( t \), we solve the equation \( 3t + 4 = 19 \).
3t = 15
t = 5
Now substitute \( t = 5 \) into \( 2t + 3 \):
2(5) + 3 = 10 + 3 = 13
Thus, the value is \(\boxed{13}\).
Question: A theoretical physicist models a quantum state where the sum...
E_1 + E_2 = 12, \quad E_1^2 + E_2^2 = 80
E_1^3 + E_2^3 = (E_1 + E_2)^3 - 3E_1E_2(E_1 + E_2)
First, compute \( (E_1 + E_2)^3 = 12^3 = 1728 \)

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