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Let width = \(w\), then length = \(2w\)
Perimeter = 2(length + width) = 2(2w + w) = 6w
\(6w = 36\), so \(w = 6\)
Length = \(2 imes 6 = 12\)
Area = length \( imes\) width = 12 \( imes\) 6 = 72
#### 72
### Question 7
A quadratic equation \(x^2 - 5x + 6 = 0\) has roots \(r_1\) and \(r_2\...
Using the identity \(r_1^2 + r_2^2 = (r_1 + r_2)^2 - 2r_1r_2\)
\(r_1 + r_2 = 5\) (sum of roots)

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