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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📝 Recent Posts

Un jardin rectangulaire mesure 15 mètres de long et 10 mètres de large...
Soit \( x \) la largeur du chemin.
Les nouvelles dimensions sont \( (15 + 2x) \) par \( (10 + 2x) \).
L'équation est \( (15 + 2x)(10 + 2x) = 264 \).
Développez : \( 150 + 30x + 20x + 4x^2 = 264 \).
Simplifiez : \( 4x^2 + 50x - 114 = 0 \).
Résolvez en utilisant la formule quadratique : \( x = \frac{-50 \pm \s...
Calculez : \( x = \frac{-50 \pm \sqrt{2500 + 1824}}{8} = \frac{-50 \pm...
Approximativement : \( x = \frac{-50 \pm 65,74}{8} \).
Choisissez la solution positive : \( x = \frac{15,74}{8} \approx 1,97...

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