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R = \fracabc4A - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📝 Recent Posts

C) False, since area is $ r \cdot s $ only if $ r $ is inradius
D) False — area is $ \frac{1}{2}ab $, and $ r s = r \cdot \frac{a+b+c}...
E) $ r s = \frac{ab}{2} $ — true
But best choice:
D) False — although $ r s = \frac{ab}{2} $, the statement area equals...
Best:
C) False — the identity $ A = r s $ is valid only if $ r $ is the inra...
Wait: $ A = r s $ is always true for inradius $ r $. So area is $ r s...
So the statement the area of the circle over the area of the triangle...
So correct claim is proven. Best choice:

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