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Home » Let’s try constant functions first. Suppose $ f(x) = c $ for all $ x $. Then: - Portal da AcÃºstica

Let’s try constant functions first. Suppose $ f(x) = c $ for all $ x $. Then: - Portal da AcÃºstica

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Mar 01, 2026

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r = \frac{a + b - c}{2}
where $ a $ and $ b $ are the legs and $ c $ is the hypotenuse. Substi...
r = \frac{3k + 4k - 5k}{2} = \frac{2k}{2} = k
So $ k = r $. Now compute the area of the triangle:
\text{Area} = \frac{1}{2} \cdot 3k \cdot 4k = 6k^2 = 6r^2
The area of the inscribed circle is:
\pi r^2
Thus, the ratio of the area of the circle to the area of the triangle...
\frac{\pi r^2}{6r^2} = \frac{\pi}{6}
Therefore, the ratio is $ \boxed{\frac{\pi}{6}} $.

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