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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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A ball is thrown upwards with an initial velocity of 20 m/s from a hei...
The equation of motion is \( h(t) = -rac{1}{2}gt^2 + v_0t + h_0 \).
Substitute \( g = 9.8 \), \( v_0 = 20 \), and \( h_0 = 50 \):
\( h(t) = -4.9t^2 + 20t + 50 \).
Set \( h(t) = 0 \) to find when it hits the ground:
\( -4.9t^2 + 20t + 50 = 0 \).
Solve using the quadratic formula: \( t = rac{-b \pm \sqrt{b^2 - 4ac}...
The discriminant \( \Delta = 20^2 - 4(-4.9)(50) = 400 + 980 = 1380 \).
\( t = rac{-20 \pm \sqrt{1380}}{-9.8} \).
Only the positive root is valid:

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