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📅 February 28, 2026 👤 scraface

Feb 28, 2026

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\( P(X=5) = \binom{150}{5} (0.03)^5 (0.97)^{145} \).
Approximate with Poisson: \( \lambda = 150 \times 0.03 = 4.5 \).
\( P(X=5) = \frac{e^{-4.5} (4.5)^5}{5!} \).
\( e^{-4.5} \approx 0.011109 \), \( 4.5^5 = 1845.5625 \), \( 5! = 120...
\( P = \frac{0.011109 \times 1845.5625}{120} \approx \frac{20.48}{120}...
More accurately: \( P = \binom{150}{5} (0.03)^5 (0.97)^{145} \).
\( \binom{150}{5} = \frac{150 \cdot 149 \cdot 148 \cdot 147 \cdot 146}...
\( (0.03)^5 = 2.43 \times 10^{-8} \)
\( (0.97)^{145} = e
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Thus, the number of such genetic markers in the first 100 terms is:
Question:** A statistician is modeling data points that follow a discr...
Solution:** First, determine how many positive integers \( n \) satisf...
First, factor 120:
= 2^3 \cdot 3 \cdot 5
The total number of positive divisors of 120 is:
Now, list all divisors of 120:
1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120
Among these, the divisors \( \leq 60 \) are all except 120. So there a...
There are 60 positive integers from 1 to 60.

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