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Home » D: $4\pi \sqrt1 + \frac116\pi^2$ - Portal da AcÃºstica

D: $4\pi \sqrt1 + \frac116\pi^2$ - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

S(7,2) = 2^{6} - 1 = 64 - 1 = 63
Alternatively, each object can go into one of the two subsets, giving...
Thus, the number of distinct groupings is \(\boxed{63}\).
Question:** A data analyst in Toronto is analyzing sequences of 8 diag...
We are to count the number of binary sequences of length 8 with exactl...
First, place the 5 N's. This creates 6 possible "gaps" where P's can b...
\(_ \, N \, _ \, N \, _ \, N \, _ \, N \, _ \, N \, _ \) → 6 gaps.
We must place 3 P's into these 6 gaps, with at most one P per gap (to...
The number of ways to choose 3 distinct gaps from 6 is:
\binom{6}{3} = 20

📝 Recent Posts

eta^2 = (1 - i)^2 = 1 - 2i + i^2 = 1 - 2i - 1 = -2i
eta^4 = (-2i)^2 = 4i^2 = -4
eta^4 + 3 = -1 = a(1 - i) + b = a - ai + b
Imaginary part: \( -a = 0 \Rightarrow a = 0 \), then \( b = -1 \)
So both give \( a = 0 \), \( b = -1 \)
Conclusion: the remainder is constant \( -1 \)
Alternatively, polynomial division confirms:
Divide \( u^4 + 0u^3 + 0u^2 + 0u + 3 \) by \( u^2 - 2u + 2 \)
First: \( u^4 \div u^2 = u^2 \), multiply: \( u^2(u^2 - 2u + 2) = u^4...
Subtract: \( (u^4 + 0u^3 + 0u^2) - (u^4 - 2u^3 + 2u^2) = 2u^3 - 2u^2 \...

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