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Home » Case 3: 4 ML: \(\binom44 = 1\) - Portal da AcÃºstica

Case 3: 4 ML: \(\binom44 = 1\) - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 A committee of 4 people is to be chosen from 6 men and 5 women. What is the probability that the committee includes at least 2 women?

📌 Total ways to choose 4 from 11: \( \binom{11}{4} = 330 \).

📌 Favorable outcomes: committees with at least 2 women = (2W,2M) + (3W,1M) + (4W,0M).

📌 Total favorable = 150 + 60 + 5 = 215.

📌 Probability = \( \frac{215}{330} = \frac{43}{66} \).

📌 #### 43/66

📌 The equation \( \log_2(x - 1) + \log_2(x + 1) = 3 \) has a solution. What is it?

📌 Using logarithmic identity: \( \log_2[(x - 1)(x + 1)] = 3 \Rightarrow \log_2(x^2 - 1) = 3 \).

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