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Home » Can Love Be More Powerful? The Hidden Truth About Boy-Girl Friendship Survival! - Portal da AcÃºstica

Can Love Be More Powerful? The Hidden Truth About Boy-Girl Friendship Survival! - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 $ c_2 = s\left(\frac{1}{2}\right) = \frac{1}{2} - \frac{1}{5} \left(\frac{1}{2}\right)^5 = \frac{1}{2} - \frac{1}{5} \cdot \frac{1}{32} = \frac{1}{2} - \frac{1}{160} = \frac{80 - 1}{160} = \frac{79}{160} $

📌 $ c_3 = s\left(\frac{79}{160}\right) = \frac{79}{160} - \frac{1}{5} \left(\frac{79}{160}\right)^5 $

📌 First compute $ \left(\frac{79}{160}\right)^5 $. Since this is tedious by hand, we compute step-by-step:

📌 Let $ a = \frac{79}{160} $. Then $ a^2 = \frac{6241}{25600} $,

📌 $ a^3 = \frac{79 \cdot 6241}{160 \cdot 25600} = \frac{493039}{4096000} $,

📌 $ a^5 = a^3 \cdot a^2 = \frac{493039}{4096000} \cdot \frac{6241}{25600} = \frac{493039 \cdot 6241}{4096000 \cdot 25600} $

📌 Rather than compute the full fraction, note the requirement is $ c_3 = a - \frac{a^5}{5} $. But since $ a^5 $ is small, we compute numerically:

📌 $ \frac{79}{160} = 0.49375 $

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