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Home » 2r - (3 - \sqrt5)r + 5 - \sqrt5 = 0 - Portal da AcÃºstica

2r - (3 - \sqrt5)r + 5 - \sqrt5 = 0 - Portal da AcÃºstica

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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Factor out \(-16\) from \( y \)-terms:
-16(y^2 - 4y)
y^2 - 4y = (y - 2)^2 - 4
-16((y - 2)^2 - 4) = -16(y - 2)^2 + 64
Substitute and simplify:
Substitute squares back into the equation:
9(x - 3)^2 - 81 - 16(y - 2)^2 + 64 = 71
9(x - 3)^2 - 16(y - 2)^2 = 88
Normalize the equation:
Divide the entire equation by 88:

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5**Question:
Compute the sum of the roots of the equation \( v\sqrt{v} - 4v + 5\sqr...
Let's transform the given equation using a substitution. Let \( x = \s...
x^2 \cdot x - 4x^2 + 5x - 6 = 0
which simplifies to:
x^3 - 4x^2 + 5x - 6 = 0
Now, we need to find the sum of the roots of this cubic equation. In a...

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