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\( \frac43 \times 12 = 16 \text cups \). - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 2Question: Let $ f $ be a function such that $ f(x^2 + 3) = 2x^4 + 10x^2 + 11 $. Find $ f(x^2 - 3) $.

📌 Solution: Let $ y = x^2 + 3 $. Then $ x^2 = y - 3 $. Substituting into the given equation:

📌 f(y) = 2(y - 3)^2 + 10(y - 3) + 11 = 2(y^2 - 6y + 9) + 10y - 30 + 11 = 2y^2 - 12y + 18 + 10y - 19 = 2y^2 - 2y - 1.

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To find the intersection of the lines \( y = 2x + 3 \) and \( y = -x +...
2x + 3 = -x + 7
Add \( x \) to both sides:
3x + 3 = 7
3x = 4

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