= \frac12 \left( 1 + \frac12 + \sum_k=3^50 \frac1k \right) - \left( \frac12 + \sum_k=3^50 \frac1k + \frac151 \right) + \frac12 \left( \sum_k=3^50 \frac1k + \frac151 + \frac152 \right). - Portal da Acústica
Mar 01, 2026
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