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#### Center: (3, -2), Radius: 5 - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 |ec{OB}| = \sqrt{(-1 - \sqrt{7})^2 + (1 - \sqrt{7})^2} = \sqrt{(1 + 2\sqrt{7} + 7) + (1 - 2\sqrt{7} + 7)} = \sqrt{16 + 8} = \sqrt{24} = 2\sqrt{6}

📌 \cos heta = rac{-12}{(2\sqrt{6})(2\sqrt{6})} = rac{-12}{24} = -rac{1}{2} \Rightarrow heta = rac{2\pi}{3}

📌 The area of the circular sector is:

📌 A_{ ext{sector}} = rac{1}{2} r^2 heta = rac{1}{2} \cdot 16 \cdot rac{2\pi}{3} = rac{16\pi}{3}

📌 Area of triangle \(OAB\):

📌 A_{ ext{triangle}} = rac{1}{2} ab \sin heta = rac{1}{2} (2\sqrt{6})(2\sqrt{6}) \sin\left(rac{2\pi}{3}

📌 ight) = rac{1}{2} \cdot 24 \cdot rac{\sqrt{3}}{2} = 6\sqrt{3}

📌 Area of segment (the smaller region bounded by the chord and arc) is:

🔥 Popular Posts

6^2 = 36 \Rightarrow 4 \cdot 36 = 144
6^1 = 6 \Rightarrow 3 \cdot 6 = 18
6^0 = 1 \Rightarrow 2 \cdot 1 = 2
+ 144 = 1224, \quad 1224 + 18 = 1242, \quad 1242 + 2 = 1244
So, the base-ten equivalent is:
oxed{1244}
Question:** Find the smallest positive integer \(n\) such that \(n^3\)...
We seek the smallest \(n > 0\) such that:
n^3 \equiv 888 \pmod{1000}
This means \(n^3 \equiv 888 \pmod{8}\) and \(n^3 \equiv 888 \pmod{125}...

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