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- \left( \frac80101 \right)^3 - Portal da AcÃºstica

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 A = l(40 - l) = 40l - l^2

📌 Maximize the quadratic function:

📌 The function \( A = -l^2 + 40l \) is a downward-opening parabola. The maximum occurs at the vertex:

📌 l = -\frac{b}{2a} = -\frac{40}{2(-1)} = 20

📌 Thus, \( w = 40 - 20 = 20 \).

📌 Calculate the maximum area:

📌 A = 20 \times 20 = 400

📌 The largest possible area is \(\boxed{400}\) square meters.

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+ 240 = 960 \text{ km}^2
\boxed{960}
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Repeat the process:
Divide \( 2x^2 \) by \( x^2 \) to get \( 2 \).
Multiply \( 2 \) by \( x^2 + 1 \) to get \( 2x^2 + 2 \).
The remainder is \(-1\). Therefore, the remainder when \( x^4 + 3x^2 +...
A science administrator is reviewing a grant application involving the...
To find the center of the hyperbola, we rewrite the equation in standa...
9x^2 - 54x - 16y^2 + 64y = 71
Complete the square for \( x \):
Factor out 9 from \( x \)-terms:
9(x^2 - 6x)

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